Question

Sendo a função , os limites: são, respectivamente:

Answer 1

$\mathsf{\lim_{x \to {2}^{+}}f(x)}\\=\mathsf{\lim_{x \to 2}{x}^{2}-2={2}^{2}-2=2}$

$\mathsf{\lim_{x \to {2}^{ - }}f(x)} \\ = \mathsf{\lim_{x \to {2}}2x + 2 = 2.2 + 2 = 6}$

$\huge\mathsf{\lim_{x \to 2}f(x) = \not\exists}$

$\huge\boxed{\boxed{\mathsf{Alternativa\:a}}}$