Question

Sendo a função f:IR tal que f(x)=1+x²/x,calcule:a) f (2)b) f (-2)c) f (1/4)d) f (-1/4)

Answer 1

Oi Cina

f(x) = (1 + x²)/x

f(2) = (1 + 4)/2 = 5/2
f(-2) = (1 + 4)/-2 = -5/2
f(1/4) = (1 + 1/16)/(1/4) = (17/16)/(1/4) = (17/16)*(4/1) = 17/4 
f(-1/4) = (1 + 1/16)/(-1/4) = (17/16)/(-1/4) = (17/16)*(-4/1) = -17/4 

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