Question

Sendo A=5^0-2^-2,B=(1-1/2)^-1,C=12^0-3,Calcule Em Seu Caderno:
(b-a)^c
(ab/c)^c

Answer 1

Lembrando, todo numero elevado a zero é 1 !

$A=1- \frac{1}{ 2^{2}} => 1- \frac{1}{4} => \frac{4-1}{4} => \frac{3}{4}$

$B= (1-\frac{1}{2}) ^{2} => (\frac{2-1}{2}) ^{2} => \frac{1}{4}$

$C=1-3=>-2$

$(B-A) ^{c}= ( \frac{1}{4}- \frac{3}{4} ) ^{-2}=> (\frac{1-3}{4} ) ^{2}=> (\frac{-2}{4} ) ^{2}=> \frac{4}{16} => \frac{1}{4}$

$( \frac{A.B}{C} ) ^{c}= (\frac{ \frac{3}{4}. \frac{1}{4} }{-2} ) ^{-2}=> (\frac{ \frac{3}{16} }{-2}) ^{-2}=> (\frac{3}{16} . \frac{1}{-2}) ^{-2} =>( \frac{3}{-32} ) ^{-2} => \frac{1}{( \frac{3}{32}) ^{2} } =>$

$\frac{1}{ \frac{9}{1024} } => \frac{1}{1} . \frac{1024}{9} => \frac{1024}{9}$