Question

SENDO A=(3 2) e B=(3 -1) e C=(4 2)
(5 1) (2 0) (-6 0)CALCULE
a)AB b)AC c)BC

Answer 1

Xb = 3, Xa = 3
Yb = -1, Ya = 2

dab = √(Xb - Xa)² + (Yb - Ya)²
dab = √(3 - 3)² + (-1 - 2)²
dab = √0 + 9
dab = √9
dab = 3

Xc = 4, Xa = 3
Yc = 2, Ya = 2

dac = √(Xc - Xa)² + (Yc - Ya)²
dac = √(4 - 3)² + (2 - 2)²
dac = √1 + 0
dac = √1
dac = 1

Xc = 4, Xb = 3
Yc = 2, Yb = -1

dbc = √(Xc - Xb)² + (Yc - Yb)²
dbc = √(4 - 3)² + (2 - (-1))²
dbc = √1² + 3²
dbc = √1 + 9
dbc = √10
dbc = 2√5 = 5√2 ≈ 3,2

Answer 2

a)(3x2)x(3-1)=12
b)(3x2)x((4x2)x(5x1)x(2x0)x(-6x0))=0
c)(3-1)x((4x2)x(5x1)x(2x0)x(-6x0))=0