Question

Sendo A=2x^3+3x^2+14; B=x^2-9 e C=4x+12, calcule
a) A+B
b) A-B
c) A.C

Answer 1

a) A + B = $(2 x^{3} +3 x^{2} +14) + (x^{2} -9) = 2 x^{3} + 4 x^{2} +5$
b) A - B = $(2 x^{3} +3 x^{2} +14) - (x^{2} -9) = 2 x^{3} + 2 x^{2} +23$
c) A * C = $(2 x^{3} +3 x^{2} +14) * (4x + 12 ) = 8 x^{4} + 12 x^{3} +56x + 24 x^{3} +36 x^{2} +168$ = $8 x^{4} + 36 x^{3} +36 x^{2} + 56x +168$