Question

Sendo a=(2^48+4^22-2^46)/(2^2.4^21 ),obtenha o valor de (a/13)^(-1).

Answer 1

a = 2^48 + 4^22 - 2^46  

a = 2^48 + (2²)^22 - 2^46  

a = 2^48 + 2^44 - 2^46 = 2^44( 16 + 1 - 4) = 13* 2^44  

a = 13*2^44  

..........................  

(4a)^-1 =  

(4*13*2^44)^-1 =  

13*2² * 2^44 =  

(13*2^46)^-1 =  

(4a)^-1 = 1/(13*2^46)