Question

sendo A=[2 3 0 0 1 2 1 3 2],calcule aplicando sarrus
a)det A
b) det At

Answer 1

Boa noite Freitas

2   3   0   2   3
0   1   2   0   1
1   3   2   1   2

det = 4 + 6 + 0 - 0 - 12 - 0 = -2


2  0  1   2   0
3  1  3   3   1
0  2  2   0   2

det = 4 + 0 + 6 - 0 - 12 - 0 = -2

det(A) = det(At)