Question

Sendo a= [2 1][ 3 2] b =[1 5][2 -2] c= [2 0][4 -6] determine.

A) a^t + b - c

B) 3.a^t

Answer 1

$A = \left[\begin{array}{cc}2&1\\3&2\end{array}\right] --\ \textgreater \ A^{t} = \left[\begin{array}{cc}2&3\\1&2\end{array}\right]$

A)$A^{t} + B - C$
$\left[\begin{array}{cc}2&3\\1&2\end{array}\right] + \left[\begin{array}{cc}1&5\\2&-2\end{array}\right] - \left[\begin{array}{cc}2&0\\4&-6\end{array}\right] \\\\ \left[\begin{array}{cc}2+1-2&3+5-0\\1+2-4&2-2-(-6)\end{array}\right] \\\\ \left[\begin{array}{cc}1&8\\-1&6\end{array}\right]$

B) 
$3A^{t} = \left[\begin{array}{cc}3.2&3.3\\3.1&3.2\end{array}\right] --\ \textgreater \ 3A^{t} = \left[\begin{array}{cc}6&9\\3&6\end{array}\right]$