Question

Sendo  a= (0,02)^-2  e b= (0,004)^-2 , obtenha o valor de:
 
A) a × b ^-1
 
B) b/a
 
C) a × 10^-3 + b × 10^-2

Answer 1

Sendo:
$a=0,02^{-2} = (\frac{2}{100})^{-2} = (\frac{100}{2})^2 = 50^2 = 2500$

e
$a=0,004^{-2} = (\frac{4}{1000})^{-2} = (\frac{1000}{4})^2 = 250^2 = 62500$

A) a × b⁻¹ = 2500 * (1/62500) = 0,04

B) b/a = 62500/2500 = 25

C) a × 10^-3 + b × 10^-2 = (1/2500³) + (1/62500²) = Zero de tão pequeno!

Ik_Lob