Question

sendo Δ =0 calcule 2x²-8X-M-1=0

Answer 1

$b^{2}-4ac= 0 \\ (-8)^{2}-4*2*(-m-1)=0 \\ 64-8(-m-1)=0 \\ 64+8m+8=0 \\ 72+8m=0 \\ 8m=-72 \\ \\ m= \frac{-72}{8} \\ \\ m= -9$