Matemática, perguntado por juUfam, 1 ano atrás

Sejam P(1,-1,2) u (3,-3,1) v (1,1,1) Obtenha a tripla de coordenadas de (p-2u)+v

Soluções para a tarefa

Respondido por andresccp
2
P=(1,-1,2)\\U=(3,-3,1)\\V=(1,1,1)\\\\\ [P-2U]+V = [(1,-1,2)-2(3,-3,1)]+(1,1,1)\\\\\ [P-2U]+V = [(1,-1,2)-(6,-6,2)]+(1,1,1)\\\\\ [P-2U]+V = [(1-6), (-1-(-6)) , (2-2)]+(1,1,1)\\\\\ [P-2U]+V = [(-5.5.0)]+(1,1,1)\\\\\ [P-2U]+V = (-5,5,0)+(1,1,1)\\\\\ [P-2U]+V = (-5+1),(5+1),(0+1)\\\\\ [P-2U]+V = (-4,6,1)
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