sejam m1=(1,2), m2=(3,4) e m3(1,-1) os pontos medios dos lados de um triangulo.determine as coodernadasdos vertices desse triangulo
Soluções para a tarefa
M1=(1,2), M2=(3,4) , M3(1,-1)
explicação
M1 = (A + B)/2 , M2 = (A + C)/2, M3 = (B + C)/2
M1 + M2 - M3
A/2 + B/2 + A/2 + C/2 - B/2 - C/2 = A/2 + A/2 = A
A(x,y) = M1(x,y) + M2(x,y) - M3(x,y)
A(x,y) = (1,2) + (3,4) - (1,-1) = (1+3-1,2+4+1)
A(3,7)
B(x,y) = M2(x,y) + M3(x,y) - M1(x,y)
B(x,y) = (3,4) + (1,-1) - (1,2) = (3+1-1,4-1-2)
B(3,1)
C(x,y) = M1(x,y) + M3(x,y) - M2(x,y)
C(x,y) = (1,2) + (1,-1) - (3,4) = (1+1-3,2-1-4)
C(-1,-3)
A(3,7)
B(3,1)
C(-1,-3) M1=(1,2), M2=(3,4) , M3(1,-1)
explicação
M1 = (A + B)/2 , M2 = (A + C)/2, M3 = (B + C)/2
M1 + M2 - M3
A/2 + B/2 + A/2 + C/2 - B/2 - C/2 = A/2 + A/2 = A
A(x,y) = M1(x,y) + M2(x,y) - M3(x,y)
A(x,y) = (1,2) + (3,4) - (1,-1) = (1+3-1,2+4+1)
A(3,7)
B(x,y) = M2(x,y) + M3(x,y) - M1(x,y)
B(x,y) = (3,4) + (1,-1) - (1,2) = (3+1-1,4-1-2)
B(3,1)
C(x,y) = M1(x,y) + M3(x,y) - M2(x,y)
C(x,y) = (1,2) + (1,-1) - (3,4) = (1+1-3,2-1-4)
C(-1,-3)
A(3,7)
B(3,1)
C(-1,-3)