Question

sejam log8 128=X, log4 64=y, e log2 32=z ; então x+y+z é igual a:​

Answer 1

log8 128=X => 2^3x = 2^7 => x= 7/3

log4 64=y => 4^y = 4^3 ==> y=3

log2 32=z => 2^z = 2^5 ==> z=5

x+y+z = 8 +7/3 = 31/3 ✓