Sejam f a função dada por f(x) = 2x + 4 e g a função dada por g(x) = 3x - 2. A função fog deve ser dada por?
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• ![f(x)=2x+4 f(x)=2x+4](https://tex.z-dn.net/?f=f%28x%29%3D2x%2B4)
•![g(x)=3x-2 g(x)=3x-2](https://tex.z-dn.net/?f=g%28x%29%3D3x-2)
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Então,
![(f\circ g)(x)\\\\ =f\big(g(x)\big)\\\\ =2\,g(x)+4\\\\ =2\cdot (3x-2)+4\\\\ =6x-4+4\\\\\\ \therefore~~\boxed{\begin{array}{c}(f\circ g)(x)=6x\end{array}} (f\circ g)(x)\\\\ =f\big(g(x)\big)\\\\ =2\,g(x)+4\\\\ =2\cdot (3x-2)+4\\\\ =6x-4+4\\\\\\ \therefore~~\boxed{\begin{array}{c}(f\circ g)(x)=6x\end{array}}](https://tex.z-dn.net/?f=%28f%5Ccirc+g%29%28x%29%5C%5C%5C%5C+%3Df%5Cbig%28g%28x%29%5Cbig%29%5C%5C%5C%5C+%3D2%5C%2Cg%28x%29%2B4%5C%5C%5C%5C+%3D2%5Ccdot+%283x-2%29%2B4%5C%5C%5C%5C+%3D6x-4%2B4%5C%5C%5C%5C%5C%5C+%5Ctherefore%7E%7E%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%28f%5Ccirc+g%29%28x%29%3D6x%5Cend%7Barray%7D%7D)
Bons estudos! :-)
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Então,
Bons estudos! :-)
Lukyo:
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