Question

sejam as funçoes f(x) = x² -2x + 1 e g(x) = 2x + 1 a) g(f(x)) b)g(f(2)) c )f(f(1))

Answer 1

f(x) = x² -2x + 1 e g(x) = 2x + 1


a) g(f(x)) =  2(x² -2x + 1) + 1 ==> 2x² - 4x + 2 + 1 ==>  2x² - 4x + 3

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b)g(f(2)) = 3

f(2) = 2² - 2(2) + 1 ==> 4 - 4 + 1 ==> 1

g(1) = 2(1) + 1 ==> 2 + 1 ==> 3
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c )f(f(1)) = 1

f(x) = 1² - 2(1) + 1 ==> 1 - 2 + 1 = 0

f(f(x)) = 0² - 2(0) + 1 ==> 0 - 0 + 1 = 1