Question

Sejam as funções f(x)=2x – 4 e g(x)= 3x + a. Se f(1)–g(0)= 6, quanto vale f(2)+5g(7)=?

Resposta: 65 (mostrem cálculo.)

Answer 1

f(1) = 2 -4 → -2
g(0) = a

-2 -a = 6
-a = 6 +2
a = -8

f(2) = 2*2 -4 → 0
g(7) = 3*7 -8 → 13

0 + 5*13
65

Answer 2

f(x)=2x – 4 e g(x)= 3x + a.
f(1)–g(0)= 6
quanto vale f(2)+5g(7)=?

f(1)= 2.1 - 4 = 2 - 4 = - 2
g(0) = 3.0 + a = 0+a = a

f(1)-g(0)= 6
- 2 - a = 6
-2-6 = a
- 8 = a
a= - 8

g(x) = 3x + a
g(7)= 3.7 - 8
g(7)= 21 - 8
g(7) = 13

f(x) = 2x - 4
f(2) = 2.2 - 4 = 4 - 4 = 0

= f(2) + 5g(7)
= 0 + 5.13
= 65

R.: 65