Question

Sejam as funções f e g de R em R definidas por f(x)=x²-4x+10 e g(x)=-5x+20. O valor de (f(4))²-g(f(4))/f(0)-g(f(0)) é:

urgente!!!

Answer 1

Olá,

$\frac{(f(4))^2-g(f(4))}{f(0)-g(f(0))} =\frac{(4^2-4(4)+10)^2-g(4^2-4(4)+10)}{0^2-4(0)+10-g(0^2-4(0)+10)}=\frac{100-g(10)}{10-g(10)}=\\\\ \frac{100-(-50+20)}{10-(-50+20)}= \frac{100+30}{10+30} = \frac{130}{40} =\boxed{ \frac{13}{4} }$