Question

Seja z = √ 2 + x² + y², x = 2t +1 e y = t³ . Então dz/dt vale :

Answer 1

Olá Hferraz 

z = √2 + x² + y² 

x = 2t + 1

y = t³ 

x² = (2t + 1)² = 4t² + 4t + 1

y² = t⁶ 

z = √2 + x² + y² 

z = √2 + 4t² + 4t + 1 + t⁶  

derivada dz/dt 

z' = 6t⁵ + 8t + 4 

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