Question

Seja raiz de 13 ao quadrado menos 12 ao quadrado igual a raiz n de 125. O valor de n é?

Answer 1

$\sqrt{13^2-12^2}= \sqrt[n]{125}\\\\ \sqrt{(12+1)^2-12^2}= \sqrt[n]{125}\\\\\sqrt{(12^2+2*12*1+1^2)-12^2}= \sqrt[n]{125}\\\\\sqrt{12^2+25-12^2}= \sqrt[n]{125}\\\\\sqrt{25}= \sqrt[n]{125}\\\\5= \sqrt[n]{5^3}\\\\5=5^{\frac{3}{n}}\\\\1=\frac{3}{n} \\\\n=3$

Answer 2

Resposta:

Explicação passo-a-passo:

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