Question

Seja g a função definida por g(x) = 3x2 – 6x – 3. Calcule g(0), g(-1), g(a), g(-a) e g(x+1).

Answer 1

g(0) = -3

g(-1) = 3 + 6 - 3 = 6

g(a) = 3a² - 6a - 3

g(x +1) = 3(x + 1)² - 6(x +1) - 3 = 3(x² + 2x +1) - 6x - 6 - 3 = 

= 3x² + 6x - 6x + 3 - 3 - 6 = 3x² - 6

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05/04/2016
Sepauto - SSRC
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