Question

Seja f(x)=2X³-3x+1, calcule:
Calcule f(√2/3)

Answer 1

Resposta:

$f( \sqrt{ \frac{2}{ 3} } ) = 2 \sqrt{ \frac{2}{3} ^{3} } - 3 \sqrt{ \frac{2}{3} } + 1 \\ f( \sqrt{ \frac{2}{3 } } = 2 \times \frac{2}{3} \sqrt{ \frac{2}{3} } - 3 \sqrt{ \frac{2}{3} } + 1 \\ f( \sqrt{ \frac{2}{3} }) = \frac{4}{3} \sqrt{ \frac{2}{3} } - 3 \sqrt{ \frac{2}{3} } + 1 \\ f( \sqrt{ \frac{2}{3} } ) = - \frac{5}{3} \sqrt{ \frac{2}{3} } + 1$