Question

seja f: R⇒R definida por f(x)= x2-5x+4 calcule
A) f(1)
B) f(2)
C) f (-2)

Answer 1

A)

y = x² - 5x + 4
y = 1² - 5*1 + 4
y = 0

B)
y = 2² - 5 * 2 + 4
y = 4 - 10 + 4
y = -2

C)

y = -2² - 5 * -2 + 4
y = 4 + 10 + 4
y = 14

Answer 2

A) f(x)= (1)² - 5(1) +4 =1 -5 +4=0

B) f(x)= (2)² - 5(2) +4 =4 -10 +4= 8-10= -2

C) f(x)= (-2)² - 5(-2) +4 = 4+ 25 +4=32