Question

Seja f: R -> Ruma função definida pela lei f(x)=x²-x+1. Determine:

 

a) f(0)

b)-2

c) f(2)+f(-2)

d)f (\sqrt{2}

 

Answer 1

 f(x) = x²-x+1

 

a)  

f(0) =0²-0+1

f(0) = 1

 

b)

f(x) = -2

-2 = x²-x+1

x² - x +3 = 0

 

(-b ±√(b²-4ac))/2

(1 ±√(1-4.3))/2

(1 ±√-11)/2

x = 1/2

 

c)

2²-2+1+(-2)²-(-2)+1

4-2+1+4+2+1

3+7

10

 

d) ???