Question

Seja f=R=>R a função dada por f(x)=x²/x-1 qual é o valor de f(2)+f(0)?

Answer 1

Resolução da questão, veja:

Primeiramente vamos determinar f (2) e f (0), depois fazemos a soma deles, veja:

Determinando f (2):

$\mathtt{f(x)=\dfrac{x^{2}}{x-1}}~\to~\mathtt{f(2)}}}\\\\\\\\\ \mathtt{f(2)=\dfrac{2^{2}}{2-1}}}}}}\\\\\\\\\ \mathtt{f(2)=\dfrac{4}{1}}}}}\\\\\\\\\ \Large\boxed{\boxed{\boxed{\boxed{\mathtt{f(2)=4.}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}$

Determinando f (0):

$\mathtt{f(x)=\dfrac{x^{2}}{x-1}}~\to~\mathtt{f(0)}}}\\\\\\\\\ \mathtt{f(0)=\dfrac{0^{2}}{0-1}}}}}}\\\\\\\\\ \mathtt{f(0)=\dfrac{0}{0}}}}}\\\\\\\\\ \Large\boxed{\boxed{\boxed{\boxed{\mathtt{f(0)=0.}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}$

Pronto, agora que temos f (2) e f (0), podemos determinar f (2) + f (0), vejamos:

$\mathtt{f(2)+f(0)}}~\to~\mathtt{f(2)=4~\textsf{e}~f(0)=0}}}}}}}\\\\\\\\\ \mathtt{f(2)+f(0)=4+0}}\\\\\\\\\\ \Large\boxed{\boxed{\boxed{\boxed{\mathtt{f(2)+f(0)=4.}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}~\mathtt{\checkmark}}}}}}}$

Espero que te ajude. '-'