Question

Seja a função y=x2-4x+6.As coordenadas do vértice são .Sendo XV =-(b/2a)

Answer 1

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Solução!

$y= x^{2} -4x+6\\\\\ Coeficientes!\\\\\\ a=1\\\\ b=-4\\\\ c=6$

Para obter as coordenadas do vértice da parábola,vamos usar essa formula.


$V\left ( \dfrac{b}{-2a}, \dfrac{\Delta}{-4a} \right )\\\\\\\\\\\ x_{V}= \dfrac{-4}{-2}=2\\\\\\ y_{V}= \dfrac{b^{2}-4.a.c }{-4a} \\\\\\\ y_{V}= \dfrac{(-4)^{2}-4.1.6 }{-4.1} \\\\\\\ y_{V}= \dfrac{16-24 }{-4} \\\\\\\ y_{V}= \dfrac{-8 }{-4}=2 \\\\\\\ Logo!\\\\\\\ \boxed{Vertice\left ( 2,2 \right )}$

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Bons estudos!