Question

Seja a função y=-3x2+2x+1. Quais são as coordenadas do vértice

Answer 1

y = -3x² + 2x + 1
a = -3 | b = 2 | c = 1

x(v) = -b/2a
x(v) = -2/2(-3)
x(v) = -2/-6
x(v) = 1/3

y(v) = -Δ/4a
y(v) = -(b²- 4ac)/4a
y(v) = -[2²-4(-3)(1)]/4(-3)
y(v) = -[4+12]/-12
y(v) = -16/-12
y(v) = 4/3

v = [x(v), y(v)]
v = [(1/3), (4/3)]