Question

Seja a função polinomial dada por f(x)=x14+x13+x12+...+x²+x+1. Determine f(−1),f(0),f(1). Urgente !

Answer 1

Eh soh colocar os numeros no lugar do x:

$f(x)=x^{14}+x^{13}+x^{12}+x^{11}+x^{10}+x^{9}+x^{8}+x^{7}+x^{6}+x^{5}+x^{4}+x^{3}+x^{2}+x+1\\\\\\f(-1)=(-1)^{14}+(-1)^{13}+(-1)^{12}+...+(-1)^{2}+(-1)+1\\\\f(-1)=1-1+1-1+1-1+1-1+1-1+1-1+1-1+1=1\\\\\\f(0)=0^{14}+0^{13}+0^{12}+...+0^{2}+0+1=1$

f(1) eu deixo pra vc