Question

seja a função f definida por f(x)=2x³-1 então f(0)+f(-1)+f(1/2) é?

Answer 1

f(x) = 2x^3 - 1

f(0) = 2.0^3 - 1 = 0 - 1 = -1
f(-1) = 2.(-1)^3 - 1 = 2.(-1) - 1 = -2 - 1 = -3
f(1/2) = 2.(1/2)^3 - 1 = 2.(1/8) - 1 = 1/4 - 1 = -3/4

f(0) + f(-1) + f(1/2)
(-1) + (-3) + (-3/4)
-1 - 3 - 3/4
-4 - 3/4
-16 - 3/4 = -19/4

Answer 2

 Olá! :)


f ( x ) = 2 x ^ 3 - 1

f ( 0 ) = 2 . 0 ^ 3 - 1 = 0 - 1 = - 1
f ( - 1 ) = 2 . ( - 1 ) ^ 3 - 1 = 2 . ( - 1 ) - 1 = - 2 - 1 = - 3
f ( 1 / 2 ) = 2 . ( 1 / 2 ) ^ 3 - 1 = 2 . ( 1 / 8 ) - 1 = 1 / 4 - 1 = -3 / 4

f ( 0 ) + f ( - 1 ) + f ( 1 / 2 )
( - 1 ) + ( - 3 ) + ( - 3 / 4 )
- 1 - 3 - 3 / 4
- 4 - 3 / 4
-16 - 3 / 4 = - 19 / 4

 Abraços! :)