Question

seja a função f defina por f(x)x/4.(x-6)². calcule o valor de k , sendo k= f(4+h)+ f(4-h)

Answer 1

f(4+h) = (4+h)/4(4+h-6)^2 
f(4+h) = (4+h)/4(h-2)^2 

f(4-h) = (4-h)/4(4-h-6)^2 
f(4-h) = (4-h)/4(-h-2)^2 
k= f(4+h) + f(4-h) 
k = (4+h)/4(h-2)^2 + (4-h)/4 (-h-2)^2 
k = (4+h)/4(h-2)^2 + (4-h)/4 (h+2)^2 
k = ((4+h)(h+2)^2 + (4-h)(h-2)^2)/((h-2)(h+2))^2 
k = ((4+h)(h^2+4h+4) + (4-h)(h^2-4h+4))/(h^2-4)^2 
k = 16(h^2+2)/(h^2-4)^2