Question

seja a função definida pela lei f(x)=x²-x+1

 

a) f(0)

 

b) f(1/2)

 

c) f(5)

Answer 1

 f(x)=x²-x+1
a) f(0)=0²-0+1
f(0) = 1

b) f(1/2)= (1/2)²-1/2+1
f(1/2)=1/4-1/2+1
f(1/2)= 1/4-2/4+4/4
f(1/2)=3/4

c)f(5)= 5²-5+1
f(5)=25-5+1
f(5)=21