Question

Seja =

3+8
+2
. O valor de (1),

Answer 1

Resposta:

(x+2)³=x³+6x²+12x+2³    

(x+2)³=x³+6x²+12x+8    

(x+2)³=x³+8+6x²+12x    

(x+2)³=x³+8+6x*(x+2)    

x³+8=(x+2)³-6x*(x+2)    

x³+8=(x+2)*[(x+2)²-6x]    

x³+8=(x+2)*[x²+4x+4-6x]    

x³+8=(x+2)*[x²-2x+4]    

∫ (x³+8)/(x+2)  dx    

∫ (x+2)*[x²-2x+4]/(x+2)  dx    

∫ x²-2x+4  dx  

=x³/3 -2x²/2+4x + c    

f(x)=x³/3 -x² + 4x + const.  

f(1)=1/3-1+4 + constante  

f(1)=10/3 + constante