Question

seis primeiros termos da pg (4096,1024,...)​

Answer 1

Resposta:

q = a2/a1 = 1024/4096 =1/4 ****

a2 = a1.q = 1024

an  = a1 qⁿ⁻¹

16 = 4096 * (1/4 )ⁿ⁻¹

16/4096 =  ( 1/4)ⁿ⁻¹

1/256  = ( 1/4)ⁿ⁻¹

( 1/4)⁴ =( 1/4)ⁿ⁻¹

n - 1 = 4

n = 4 + 1 = 5 ***

S5 =  a1 ( qⁿ  - 1)/ ( q - 1)

S5 = 4096[ ( 1/4)⁵  - 1 ] / (  1/4 - 1/1)

S5  = 4096. [ ( 1024  - 1 ] ]/ ( - 3/4 )

S5 =( 4096 . 1023 )/ ( -3/4 )

S5 = 4190208 :( - 3/4 )  = 4190208/1 * ( - 4/3 ) = - 16760832/3 =- 5586944 ***