Question

Segue abaixo a pergunta, quem puder favor ajuda aí, matemática aplicada!

Answer 1

a)

lim (8x-1) =8*(-1)-1=-8-1=-9

x-->-1

b)

lim (3x²+5x-7)=3*(-2)²+5*(-2)-7=12-10-7=-5

x-->-2

e)

lim √[(x²-2x-15)/(x-5)]

x-->5

_______________________________

x²-2x-15=0 ==>x'=-3  , x''=5 e a =1

x²-2x-15=a*(x-x')*(x-x'')=1*(x+3)*(x-5)

_______________________________

lim √[(x+3)*(x-5)/(x-5)]

x-->5

lim √(x+3)  =√(5+3)=2√2

x-->5

d)

lim(2x+3)/(4x²-1) =(2*2+3)/(4*2²-1)=7/15

x-->2

e)

lim (x²+x-56)/(x-7)

x-->7

x²+x-56=(x+8)*(x-7)

lim (x+8)*(x-7)/(x-7)

x-->7

lim (x+8)=15

x-->7