Question

Sebe_ Se que 3x+3y=7 se x =2m+ 1 e y= m-3 determine o valor de m de x e de y.

Answer 1

$\Large\boxed{\begin{array}{l}\sf 3x+3y=7\\\sf 3\cdot(2m+1)+3\cdot(m-3)=7\\\sf 6m+3+3m-9=7\\\sf 9m-6=7\\\sf 9m=7+6\\\sf 9m=13\\\sf m=\dfrac{13}{9}\\\\\sf x=2m+1\\\sf x=2\cdot\bigg(\dfrac{13}{9}\bigg)+1\\\sf x=\dfrac{26}{9}+1=\dfrac{35}{9}\\\\\sf y=\dfrac{13}{9}-3\\\\\sf y=\dfrac{13-27}{9}\\\\\sf y=-\dfrac{14}{9}\end{array}}$

Answer 2

$\Large\boxed {\begin{array}{l} \displaystyle \sf C\acute{a}lculo\:do\:valor\:de\:m :\\\\\displaystyle \sf3x+3y=7\\\\\displaystyle \sf 3 \cdot (2m+1)+3\cdot(m-3)=7\\\\\displaystyle \sf 6m +3+3m-9=7 \\\\\displaystyle \sf 9m-6=7\\\\\displaystyle \sf 9m = 7+6\\\\\displaystyle \sf 9=13\\\\ \displaystyle \sf m=\dfrac{13}{9} \sf\end{array}}$

$\Large\boxed {\begin {array}{l} \displaystyle \sf C\acute{a}lculo\:do\:valor\:de\:x :\\\\\displaystyle\sf x=2m+1 \\ \\ \displaystyle \sf x=2\cdot \left( \dfrac{13}{9} \right) +1\\\\\displaystyle\sf x=\dfrac{26}{9} +1=\dfrac{35}{9} \sf\end{array}}$

$\Large\boxed{\begin{array}{l} \displaystyle\sf C\acute{a}lculo\:do\:valor\:de\:y:\\\\\displaystyle \sf y=\dfrac{13}{9} -3\\\\\displaystyle\sf y=\dfrac{13-27}{9}\\\\\displaystyle \sf y=-\dfrac{14}{9} \sf\end{array}}$

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