Question

se z1=1+2i e z2= 2+3i a divisao sera?

Answer 1

$\frac{1+2i}{2+3i}\\ \\\frac{1+2i}{2+3i}.\frac{2-3i}{2-3i}\\ \\\frac{(1+2i)(2-3i)}{(2+3i)(2-3i)} \\\\\frac{(1*2+2i*2-3i*1-3i*2i)}{(2^2+3^2}\\\\\frac{(2+4i-3i-6i^2)}{(4+9}\\\\\frac{(2+4i-3i+6)}{(13}\\\\\frac{(8+i)}{(13}\\\\\frac{8}{13}+ i\frac{1}{13}$