Question

se z=3+2i é um número complexo, então z^2 é igual a:
A) 5+12i
B) 9+12i
C) 13+4i
D) 9+4i

Answer 1

$\large\boxed{\begin{array}{l}\sf z=3+2i\\\sf z^2=(3+2i)^2\\\sf z^2= 9+12i+4i^2\\\sf z^2=9+12i-4\\\sf z^2=5+12i\\\huge\boxed{\boxed{\boxed{\boxed{\sf\red{\maltese}~\blue{alternativa~A}}}}}\end{array}}$