Question

Se Z=-1+i√3/2 então z+z'+z.z' vale?

a.0
b.1
c.-1
d.-1/2
e.1/2

Answer 1

$z=-1+ \frac{ \sqrt{3} }{2} i$
 
$z`=seu~~conjugado=~-1- \frac{ \sqrt{3} }{2} i$

$z+z`+z.z`$
$-1+ \not{\frac{ \sqrt{3} }{\not2} i } -1- \frac{\not \sqrt{3} }{\not2}i~+~(-1+ \frac{ \sqrt{3} }{2} ).(-1- \frac{ \sqrt{3} }{2} )$

$-2~+~1~+ \frac{ \not \sqrt{3} }{\not2}i~- \frac{ \not\sqrt{3} }{\not2}i~-~ { \frac{ \sqrt{9}}{4} } i^2$

$-1-\frac{3(-1)}{4} =-1+ \frac{3}{4} ~~~~~~~~mmc=4$

$-4+3=-1~~~~~~~~~resposta ~~letra~~c)$