Se X² - Y² = 135 e x - y = 9, então qual é p valor de X + Y ? (Por favor me ajudem)
Soluções para a tarefa
Respondido por
2
X² - Y² = 135 (I)
X-Y = 9 (II)
Isola x em II
X-Y = 9
X = 9 + Y
Substitui em II:
X² - Y² = 135
(9 + Y)² - Y² = 135
9² + 2.9.Y + Y² - Y² = 135
81 + 18Y = 135
18Y = 135-81
18Y = 54
Y = 3
x= 9 + y
x = 9 + 3
x = 12
x=12 e y=3
X-Y = 9 (II)
Isola x em II
X-Y = 9
X = 9 + Y
Substitui em II:
X² - Y² = 135
(9 + Y)² - Y² = 135
9² + 2.9.Y + Y² - Y² = 135
81 + 18Y = 135
18Y = 135-81
18Y = 54
Y = 3
x= 9 + y
x = 9 + 3
x = 12
x=12 e y=3
Respondido por
2
a)
⇒ 
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⇒ 
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
⇒ 
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b)
⇒ 

⇒
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Portanto
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b)
⇒
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Portanto
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