Se x=-5 é a raiz da função dada por f(x) = mx-3/2 em que m € R
A) o valor de M
B) a lei que define f
C) f(0),f(2) e f(-3/4)
Anexos:
![](https://pt-static.z-dn.net/files/de9/5d9e0cdc15ac19d7c595c823f1266db7.jpg)
Soluções para a tarefa
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A raiz de uma função é o valor para x que a função se iguala a 0.
![m(-5)- \frac{3}{2} =0 m(-5)- \frac{3}{2} =0](https://tex.z-dn.net/?f=m%28-5%29-+%5Cfrac%7B3%7D%7B2%7D+%3D0)
![-5m- \frac{3}{2} =0 -5m- \frac{3}{2} =0](https://tex.z-dn.net/?f=-5m-+%5Cfrac%7B3%7D%7B2%7D+%3D0)
![-5m=\frac{3}{2} -5m=\frac{3}{2}](https://tex.z-dn.net/?f=-5m%3D%5Cfrac%7B3%7D%7B2%7D)
![m=-\frac{3}{10} m=-\frac{3}{10}](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7B3%7D%7B10%7D)
a)![m=- \frac{3}{10} m=- \frac{3}{10}](https://tex.z-dn.net/?f=m%3D-+%5Cfrac%7B3%7D%7B10%7D+)
b)![f(x)=- \frac{3x}{10} - \frac{3}{2} f(x)=- \frac{3x}{10} - \frac{3}{2}](https://tex.z-dn.net/?f=f%28x%29%3D-+%5Cfrac%7B3x%7D%7B10%7D+-+%5Cfrac%7B3%7D%7B2%7D+)
![f(x)= \frac{-3x-15}{10} f(x)= \frac{-3x-15}{10}](https://tex.z-dn.net/?f=f%28x%29%3D+%5Cfrac%7B-3x-15%7D%7B10%7D)
c)
![f(0)=- \frac{3(0)}{10} - \frac{3}{2} \\ f(0)= - \frac{3}{2} f(0)=- \frac{3(0)}{10} - \frac{3}{2} \\ f(0)= - \frac{3}{2}](https://tex.z-dn.net/?f=f%280%29%3D-+%5Cfrac%7B3%280%29%7D%7B10%7D+-+%5Cfrac%7B3%7D%7B2%7D++%5C%5C+f%280%29%3D+-+%5Cfrac%7B3%7D%7B2%7D+)
![f(2)=\frac{-3(2)-15}{10} \\ f(2)=-\frac{21}{10} f(2)=\frac{-3(2)-15}{10} \\ f(2)=-\frac{21}{10}](https://tex.z-dn.net/?f=f%282%29%3D%5Cfrac%7B-3%282%29-15%7D%7B10%7D+%5C%5C+f%282%29%3D-%5Cfrac%7B21%7D%7B10%7D)
![f(- \frac{3}{4} )=\frac{-3(- \frac{3}{4} )-15}{10} \\ f(- \frac{3}{4} )= \frac{\frac{9}{4}-15}{10} \\ f(- \frac{3}{4} )=\frac{(\frac{9-60}{4} )}{10} \\ f(- \frac{3}{4} )=(\frac{9-60}{4 \cdot 10} ) \\ f(- \frac{3}{4} )=-\frac{51}{40} f(- \frac{3}{4} )=\frac{-3(- \frac{3}{4} )-15}{10} \\ f(- \frac{3}{4} )= \frac{\frac{9}{4}-15}{10} \\ f(- \frac{3}{4} )=\frac{(\frac{9-60}{4} )}{10} \\ f(- \frac{3}{4} )=(\frac{9-60}{4 \cdot 10} ) \\ f(- \frac{3}{4} )=-\frac{51}{40}](https://tex.z-dn.net/?f=f%28-+%5Cfrac%7B3%7D%7B4%7D+%29%3D%5Cfrac%7B-3%28-+%5Cfrac%7B3%7D%7B4%7D+%29-15%7D%7B10%7D+%5C%5C+f%28-+%5Cfrac%7B3%7D%7B4%7D+%29%3D+%5Cfrac%7B%5Cfrac%7B9%7D%7B4%7D-15%7D%7B10%7D+%5C%5C+f%28-+%5Cfrac%7B3%7D%7B4%7D+%29%3D%5Cfrac%7B%28%5Cfrac%7B9-60%7D%7B4%7D+%29%7D%7B10%7D+%5C%5C+f%28-+%5Cfrac%7B3%7D%7B4%7D+%29%3D%28%5Cfrac%7B9-60%7D%7B4+%5Ccdot+10%7D+%29+%5C%5C+f%28-+%5Cfrac%7B3%7D%7B4%7D+%29%3D-%5Cfrac%7B51%7D%7B40%7D)
a)
b)
c)
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