Question

Se x=√27+√75-√48 e y=√243 qual o valor de x+y?​

Answer 1

$x = \sqrt{27} + \sqrt{75} - \sqrt{48} \\ x = \sqrt{9.3} + \sqrt{25.3} - \sqrt{16.3} \\ x = 3 \sqrt{3}+5\sqrt{3} - 4 \sqrt{3} \\ x = 4 \sqrt{3}$

$y = \sqrt{243} \\ y = \sqrt{81.3} \\ y = 9 \sqrt{3}$

$x + y = 4 \sqrt{3} + 9 \sqrt{3} = 13 \sqrt{3}$

Answer 2

Resposta:

13√3

Explicação passo-a-passo:

27|3

9|3

3|3

27=3³=3².3

√27=√3².3=√3².√3=3√3

75|3

25|5

5|5

1|

75=3.5.5=3.5²

√75=√3.5²=√3.√5²=5√3

48|2

24|2

12|2

6|2

3|3

1

48=2.2.2.2.3=2⁴.3

√48=√2⁴.3=√2⁴.√3=2².√3=4√3

243 | 3

81 | 3

27 | 3

9 | 3

3 | 3

1 | 1

243 = 3 . 3 . 3 . 3 . 3 = 3⁴.3

√243=√3⁴.3=√3⁴.√3=3²√3=9√3

x+y==

(√27+√75-√48)+√243=

(3√3+5√3-4√3)+9√3=

13√3