Question

se um dos catetos do triangulo mede 10 cm e a hipotenusa 25. quantos mede o outro cateto?

Answer 1

Use o Teorema de Pitágoras;

$a^2=b^2+c^2\to\\\\\\ 25^2=10^2+c^2\to\\\\ 625=100+c^2\to\\\\ 625-100=c^2\to\\\\ 525=c^2\to\\\\ \sqrt{525} =c\to \\\\\sqrt{3*5^2*7} =c\to \\\\ c=5 \sqrt{3*7}\to\\\\ c=5 \sqrt{21}cm$

R.: O outro cateto mede $5 \sqrt{21} cm$



$Verificando:\\\\a^2 =25cm;b=10cm;c=5 \sqrt{21} cm\\\\ a^2=b^2+c^2\\\\25^2=10^2+(5 \sqrt{21} )^2\to\\\\ 625=100+25 \sqrt{441} \to\\\\ 625=100+25 *21\\\\ 625=100+525 \to\\\\ 625=625$