Question

se tg (x + y) = 33 e tgx = 3 então tg y é igual a? heeelllpppp :)

Answer 1

Vamos lá:

$tg(x+y) = \frac{tgx+tgy}{1-tgx.tgy} \\\\ \frac{3+tgy}{1-3tgy} = 33 \\\\ 33(1-tgy) = 3+tgy \\\\ 34tgy = 30 \\\\ tgy = \frac{30}{34} \\\\ tgy = \frac{15}{17}$

Espero ter ajudado.