Question

Se Sen x = 3/4, calcule o valor de Cos x

Answer 1

Resposta:

sen(x) = 3/4

sen²(x) + cos²(x) = 1

cos²(x) = 1 - sen²(x) = 1 - 9/16 = 7/16

cos(x) = ±√7/4

tg(x) = sen(x)/cos(x) = (3/4)/(√7/4) = ±3√7/7

Answer 2

Resposta:

sen(x) = 3/4  

sen²(x) + cos²(x) = 1  

cos²(x) = 1 - sen²(x) = 1 - 9/16 = 7/16  

cos(x) = ±√7/4  

tg(x) = sen(x)/cos(x) = (3/4)/(√7/4) = ±3√7/7