Question

se sen (2x) = 1/2 então tg( x ) + cotg (x) é igual a?

Answer 1

Resposta:

[16.sen^4(x) +1]/4.sen^2(x)

Explicação passo-a-passo:

sen(2x) = sen(x+x) = sex.cosx +senx.cosx = 2.senxcosx = 1/2

cosx = 1/(4senx)

tgx = senx/1/(4senx) = 4.sen^2(x)

cotgx = 1/tgx = 1/4.sen^2(x)

tgx + cotgx = 4.sen^2(x) + 1/4.sen^2(x) = [(4.sen^2(x))^2 +1]/4.sen^2(x) =[ 16.sen^4(x) +1]/4.sen^2(x)