Question

Se seca= 2.√3/3, calcule sena, cosa e tga.

Answer 1

Resposta:

sen(a) = 1 / 2

cos(a) = √3 / 2

tg(a) = √3 / 3

Explicação passo-a-passo:

sec(a) = 2√3 / 3

sen(a):

sen²(a) + cos²(a) = 1

sen²(a) + (√3 / 2)² = 1

sen²(a) + 3 / 4 = 1

sen²(a) = 1 - 3 / 4

sen²(a) = 4 / 4 - 3 / 4

sen²(a) = 1 / 4

sen(a) = √1 / √4

sen(a) = 1 / 2

cos(a):

sec(a) = 1 / cos(a)

2√3 / 3 = 1 / cos(a)

3 / 2√3 = cos(a) / 1

cos(a) = √3 / 2

tg(a):

tg(a) = sen(a) / cos(a)

tg(a) = 1 / 2 / √3 / 2

tg(a) = 1 * 2 / 2 * √3  

tg(a) = 2 / 2√3  

tg(a) = 2√3 / 2 * 3  

tg(a) = 2√3 / 6

tg(a) = √3 / 3