Question

Se sec×=9/4,calcule sen×,cos× e tg×<br />

Answer 1

sec x = 1/cos x
9/4 = 1/cos x
  9×cos x = 4

 cos x = 4/9

sen ² x + cos² x = 1
sen² x = 1 - cos² x 
 sen² x = 1 - (4/9)²
sen² x = 1 - 16/81
 sen² x =  (81 - 16)/ 81
 sen² x =  65/81 
 sen x = √65/√81

sen x = √65/9

 tg x =sen x ÷ cos x
 tg x = √65/ 9 ÷ 4/ 9 

 tg x = √65/4