Question

Se r :4x+3y+4=0 e P(-5,2) então a distância entre r e ponto P é:

Answer 1

Distância do ponto á reta

$\large\boxed{\boxed{\boxed{\boxed{\mathsf{d_{P,r}=\dfrac{|ax_{p}+by_{p}+c|}{\sqrt{a^2+b^2}}}}}}}$

$\mathsf{d_{P,r}=\dfrac{|4.-5+3.2+4|}{\sqrt{4^2+3^2}}}$

$\mathsf{d_{P,r}=\dfrac{|-20+6+4|}{\sqrt{16+9}}}$

$\mathsf{d_{P,r}=\dfrac{10}{\sqrt{25}}}$

$\mathsf{d_{P,r}=\dfrac{10}{5}}$

$\huge\boxed{\boxed{\boxed{\boxed{\mathsf{d_{P,r}=2}}}}}$