Question

Se que 2^x-1 = 32 e que y^5 = 32 então o valor de 4^x-y é?

OBS: ^ significa elevado!

Por favor mostrar cálculos!

Answer 1

   $2^{x-1} = 32 --\ \textgreater \ 2^{x-1} =2^5--\ \textgreater \ x-1 =5 --\ \textgreater \ x =6$

  $y^5 = 32 --\ \textgreater \ y^5 = 2^5--\ \textgreater \ y = 2$

  $4^{x-y} = 4^{6-2} = 4^{4} =256$

Answer 2

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}2^{x-1} = 32\\\\2^{x-1} = 2^5\\\\x-1=5\\\\\boxed{x = 6} \end{array}\right \to \left\begin{array}{ccc}y^5=32\\\\y^5 = 2^5\\\\y = \sqrt[5]{2^5}\\\\\boxed{y = 2}\end{array}\right \to \left\begin{array}{ccc}4^{x-y}=\\\\4^{6-2} = \\\\4^{4} = \\\\\boxed{\boxed{256}}\end{array}\right$

Espero ter ajudado. =^.^=