Question

Se puder fazer detalhado

Answer 1

Resposta:

$b, x - y - 2yx^{2}$

Explicação passo-a-passo:

$\frac{x^{3} + y^{3} - 2y.(y^{2} + x^{2})}{x^{2} - y^{2} } \\\\  \frac{x^{3} + y^{3} [- 2y.y^{2} + (-2y.x^{2})]}{x^{2} - y^{2} } \\\\\frac{x^{3} + (y^{3} - 2y^{3}) -2y.x^{2}}{x^{2} - y^{2} } \\\\\frac{x^{3} -y^{3} -2y.x^{2}}{x^{2} - y^{2} } \\\\\frac{x.x.x -y.y.y -(2y.x^{2})}{x.x - y.y }\\\\x -y -(2y.x^{2})\\\\x - y - 2yx^{2}$