Question

se p(x)=x³-5x e r(x)=x³-x²-x+3 ,obtenha q(x) tal que p(x)+q(x)=r(x)

Answer 1

p(x) = x³ - 5x
r(x) = x³ - x² - x + 3
q(x) = ?

p(x) + q(x) = r(x)

Vamos isolar "q(x)":

p(x) + q(x) = r(x)
q(x) = r(x) - p(x)

Substituindo:

q(x) = r(x) - p(x)
q(x) = (x³ - x² - x + 3) - (x³ - 5x)
q(x) = x³ - x² - x + 3 - x³ + 5x
q(x) = -x² + 4x + 3

>>RESPOSTA: q(x) = -x² + 4x + 3

Answer 2

vamos isolar " q(x)"
=================
p(x) + q(x) = r(x)

q(x) = r(x) - p(x)

Vamos substituir em :

q(x) = r(x) - p(x)

q(x) = (x^3 - x^2 - x + 3) - (x^3 - 5x)

q(x) = x^3 - x^2 - x + 3 - x^3 + 5x

q(x) = - x^2 + 4x +3